#52EasyStrings· String Methods

String Manipulation Mastery

Write `analyze_text(text)` that returns a dictionary describing the text. Build the keys in exactly this order: - `"reversed"`: the text backwards. - `"vowels"`: how many characters are vowels (`a e i o u`, upper or lower case). - `"is_palindrome"`: `True` if the letters and digits, compared without case, read the same in both directions. Spaces and punctuation are ignored, and text with no letters or digits counts as a palindrome. - `"most_common"`: the character (case-sensitive, spaces excluded) that occurs most often. On a tie, the one that appears first in the text wins. Use `""` when there is no such character. - `"underscored"`: the text with every space replaced by `_`. - `"digits"`: all digit characters of the text, joined in their original order.

Input format

`text`: a string of printable ASCII characters.

Output format

A dictionary with the six keys above, in that order.

Examples

Input: text = "Never odd or even"

Output: {"reversed":"neve ro ddo reveN","vowels":6,"is_palindrome":true,"most_common":"e","underscored":"Never_odd_or_even","digits":""}

Without spaces and case the text reads `neveroddoreven` both ways. `e` occurs 4 times, more than any other character.

Input: text = "Room 101"

Output: {"reversed":"101 mooR","vowels":2,"is_palindrome":false,"most_common":"o","underscored":"Room_101","digits":"101"}

`o` and `1` both appear twice; `o` comes first.

Constraints

0 <= len(text) <= 1000

Study first

Working with Strings in Python

#python
#strings
#slicing
#string-methods